Regular+Math+Final

HONORS/ REGULAR ALGEBRA 1 MATH FINAL  1. 2x+12=30 x+6= 15 x=9

2. 2(x+8)=3(x-5) 2x+16=3x-15 16=x-15 31=x

3. x/8=5/1.2 cross multiplication! 1.2x=8*5 1.2x=40 x=40/1.2 x=33.3

How do you solve equations with an x in them, as a fraction?? ex...x/5 = 2/6 or something like that.

um okay. so u gave the example x/5=2/6. in this example, you will want to get x to be alone. x is being divided by five so to undo division u must multiply. sp now, multiply to two sides by 5. this ends up giving u x=5/3. theres ur answer. now, im not sure if i am right, but it is a possibility. make sure you get TWO explanations. ok?

This, i get. You can use cross multiplication. Like above in three. You multiply the x by the 6, and the 5 by the 2. so you end up with, 6x=10. if you divide by six you get x=10/6, so yes the answer would have to be 5/3. That is the way i know how to get it. i am still (on the exam) going to use both methods to make sure i get the answer correct. i recomend the same for all of you.

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